Velocity of a train increases uniformly from 20 kilometre per hour to 60 km per hour in fourth are the distance travelled by the train during this period is
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Explanation:
Here
intial velocity u= 20 km /hr=5.56 m/s
final velocity v=60 km/hr=16.67 m/s
the train is under uniform accerleration
t=0.2 hr=12 minutes=720 secs
a=v-u/t=0.0154 m/s²
s=ut+(1/2)at²=7994.88 m=7.99488 km.Mark as Brainliest
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