velocity of a trains changes from 2 metre per second to 25 M per second when it accelerates at a rate 2 metre per second square find the distance covered by the train
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u = 2m/s
v=25m/s
a= 2mls^2
From Newton's third equation of motion
v^2=u^2+2as
25^2 = 2^2 + 2×2×s
(625-4)/4= s
s=155.5m
v=25m/s
a= 2mls^2
From Newton's third equation of motion
v^2=u^2+2as
25^2 = 2^2 + 2×2×s
(625-4)/4= s
s=155.5m
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