Question

Velocity of an aeroplane is doubledthen kinetic emergy of aeroplane will be

Answer 1

Initial K.E =
$\frac{1}{2} m {v}^{2}$
if velocity is doubled
v = 2v

Then kinetic energy becomes

K.E=
$\frac{1}{2} m {2v}^{2}$
2 and 2 gets cancelled
and final kinetic energy is
$m {v}^{2}$

Answer 2

it is your answer hope it is helpful