Physics, asked by lamchaokip5390, 1 year ago

Velocity of an aeroplane is doubledthen kinetic emergy of aeroplane will be

Answers

Answered by Harshitha333
0
Initial K.E =
 \frac{1}{2} m {v}^{2}
if velocity is doubled
v = 2v

Then kinetic energy becomes

K.E=
 \frac{1}{2} m {2v}^{2}
2 and 2 gets cancelled
and final kinetic energy is
 m {v}^{2}

Harshitha333: Hope it helped you
Harshitha333: Mark as brainliest
Answered by greathishanth
0

it is your answer hope it is helpful

Attachments:
Similar questions