Question

velocity of an obiect changes from 2m/s to 10 m/s in 4 second
if the mass of the object is 10 kg Then now much
force will be require to do this?​

Answer 1

Given:

Initial velocity of object,u= 2 m/s

Final velocity of object,v= 10 m/s

Time taken by object,t= 4 s

Mass of object,m= 10 kg

To Find:

Force required to perform given action

Solution:

We know that,

• Acceleration a is given by

$\pink{\underline{\boxed{\bf{a=\dfrac{v-u}{t}}}}}$

• Force F is given by

$\purple{\underline{\boxed{\bf{F=ma}}}}$

where,

v is final velocity

u is initial velocity

t is time taken

m is mass

━━━━━━━━━━━━━━━━━━━━━━━━━

Let the acceleration of object be a

So,

$\longrightarrow\rm{a=\dfrac{v-u}{t}}$

$\longrightarrow\rm{a=\dfrac{10-2}{4}}$

$\longrightarrow\rm{a=\dfrac{8}{4}}$

$\longrightarrow\rm{a=2\ m/s}$

Let the force required to perform given action be F

So,

$\longrightarrow\rm{F=ma}$

$\longrightarrow\rm{F=10\times2}$

$\longrightarrow\rm\green{F=20\ N}$

Hence, the force required to perform given action is 20 N.

Answer 2

$\boxed{\rm{\blue{Find \longrightarrow }}}$

• Force?

$\boxed{\rm{\orange{Given \longrightarrow }}}$

• initial velocity[u]= 2m/s
• Final velocity [v]= 10m/s
• Time taken [t] = 4 sec
• object mass [m] = 10kg

$\boxed{\rm{\green{SoLution \longrightarrow }}}$

According to second law of motion,

$\boxed{\bf{F=ma}}$

• F=Force
• m=mass
• a=acceleration

firstly we will find the acceleration,

$\sf{a= \dfrac{10-2}{4} = \dfrac{8}{4} = 2m/s^2}$

put value of a in F=ma,

$\sf{\implies F= 10\times 2 = 20kg \ m/s^2 }$

$\boxed{\underline{\bf{\pink{\therefore Force = 20 N\bigstar}}}}$

___________________________