Question

Velocity of an object of mass 5 kg increases from 3 m/s to 7 m/s on
applying a force continuously for 2 s. Find out the force applied. If the
duration for which force acts is extended to 5 s, what will be the velocity
of the object then?​

Answer 1

Given,

• Mass = 5kg

• initial velocity=3m/s

• Final velocity=7m/s

• Time=2s

${ \: \boxed { \sf{ \bigstar}{ \: Now \: acceleration= v-u/t}}}$

$\sf{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: =7-3/2}</p><p> \\ \sf{</p><p> \: \: \: \: \: \: \: \: \: =4/2}</p><p> \\ { \sf{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: </p><p>=2m/s²}}$

So, acceleration=2m/s²

Now,

$\boxed{ \sf{{ \bigstar}{ \: F=ma}}} \\ { \sf{</p><p></p><p> \: \: \: \: \: \: \: \: \: \: \: \: \: \: =5 \times 2}}</p><p> \\ { \sf{</p><p> \: \: \: \: \: \: \: \: \: \: \: \: \: =10 \: N}}$

Hᴏᴩᴇ Iᴛꜱ Hᴇʟᴩ U ♡

Answer 2

Refer the attachment ↑