Question

velocity of an object of mass 5 kilogram increases from 3 metre per second to 7 metre per second on applying a force continuously for 2 seconds find out the force applied if the duration for which force act is extended to 5 second what will be the velocity of the object to them​

Answer 1

Explanation:

Given,

mass=5kg

t1 =2s

Initial velocity u=3m/s

Final velocity v=7m/s

t2 =5s

So,

Let the Force be F

Let the acceleration be a

So,

a= (v−u)/t

= (7−3)/2

=2m/s

So the magnitude of the applied force is 10N

And the final velocity after 5s is v

So,

v=u+at

v=3+2×5

v=13m/s

The final velocity after 5s is 13m/s

Answer 2

Given,

mass=5kg

t1=2s

Initial velocity u=3m/s

Final velocity v=7m/s

t2 =5s

So,

Let the Force be F

Let the acceleration be a

So,

a= (v−u)/t = (7−3)/2 =2m/s²

So the magnitude of the applied force is 10N

And the final velocity after 5s is v

So,

v=u+at

v=3+2×5

v=13m/s

The final velocity after 5s is 13m/s

I hope my answer will helps you ⚡✳️