Question

velocity of an object of mass 5kg increased from 3m/s to7m/s on applying force continuesly 2sec. find out the force applied if the duration for which force act it extended to 5sec what will be the velocity of the object then?​

Answer 1

Given :-

• mass = 5 kg
• initial velocity = 3 m/s
• final velocity = 7 m/s
• time taken = 2 sec

Solution :-

So, F = ?

→ [ F = m ( v - u ) / t ]

→ F = 5 ( 7 - 3 ) / 2

→ F = 35 - 15 / 2

→ F = 10 N

Now,

→ [ v = u + at ]

→ 7 = 3 + a × 2

→ 4 = 2a

→ a = 2 m/s² ⠀ ⠀⠀ ⠀ Ans ( i )

Therefore, in second case

→ [ v = u + at ]

→ v = 3 + 2 × 5

→ v = 3 + 10

→ v = 13 m/s ⠀ ⠀⠀ ⠀ Ans ( ii )

Thank You !!