Velocity of an object of mass 5kg.increases from5m/sto14
m/s on applying a force continuously for 3s What will be force applied it
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Answer:
where is question because I don't know
Answered by
0
Answer:
285 N
Explanation:
Given:
Mass=5kg
Initial velocity (u)=5m/s
Final Velocity (v)=14m/s
Time (t)=3 s
Acceleration= v^2-u^2/t
=> (14)^2-(5)^2/3
=>196-25/3=171/3=57m/s^2
We know that, Force =Mass x Acceleration
F=5 x 57= 285 N
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