velocity of an object of mass 6 kg increases from 2 m/s to 6 m/s on applying a force continuously for 5 s. Find out the force applied. If the duration for which force acts is extended to 2 s, what will be the velocity of the object then?
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Explanation:
Force=Mass*Acceleration
= ma
We know,a=change in velocity/time
Hence,a=(final velocity-initial velocity)/t
F=ma
=6*(6-2)/5
=6*4/5
=24/5N
=4.8N
Answer to First question is 4.8N.
Second question:
Given:u=2m/s,a=4/5m/s²,t=5s+2s=7s,v=?
By 1st equation of motion:
V=u+at
v=2+(4/5*5)
v=2+4m/s
v=6m/s
Hence,answer to 2nd question is 6m/s.
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