Question

velocity of any particle at any x is given by 2√a-x².Then find acceleration of particle at any x​

Answer 1

a=dv/dt; Let us differentiate v(x):

 

dv/dt=dv/dx*dx/dt=dv/dx*v, since dx/dt is velocity itself. I used a chain rule here, as you may notice.

 

dv/dx is given by:

 

dv/dx=2x+1; Thus we obtain:

 

a=dv/dt=(2x+1)*v(x)=(2x+1)*(x2+x)=2x3+3x2+x

 

Now all you have to do is to plug in x=2

 

a(x=2 m)=2*23+3*22+2=16+12+2=30 m/s2

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please mark it as the brainliest answer.