Question

Velocity of certain monochromatic light in the given transparent medium is 2.25 into 10 power 8 what is the

Answer 1

Hey dear,
Given question is incomplete.

◆ Complete question-
Velocity of certain monochromatic light in the given transparent medium is 2.25×10^8 m/s. What is (a) refractive index of medium (b) criticle angle of incidence (c) polarizing angle for medium?

◆ Answer-
i = 48.59 °
p = 53.06 °

◆ Explanation-
# Given-
v = 2.25×10^8 m/s

# Solution-
(a) Refractive index of medium -
n = c/v
n = (3×10^8) / (2.25×10^8)
n = 1.33

(b) Critical angle of incidence -
n = 1/sin(i)
i = sininv(1/n)
i = sininv(1/1.33)
i = 48.59 °

(b) Polarizing angle for medium -
tan(p) = n
p = taninv(n)
p = taninv(1.33)
p = 53.06 °

Hope this is useful...