Question

Velocity of light in air is 3×10^8m/s, while its velocity in a medium is 1.5×10^8m/s.Then,find the refractive index of this medium ?​

Answer 1

Given:-

Speed of light in air , c = 3 × 10⁸ m/s

Speed of light in medium ,v = 1.5 × 10⁸ m/s

To Find:-

Refractive index of medium ,nm

Solution:-

Using Snell's Law

• nm = c/v

where,

ng is the refractive index

c is the speed of light in air

v is the speed of light in medium

Substitute the value we get

→ nm = 3×10⁸/1.5×10⁸

→ nm = 3/1.5

→ nm = 2

Therefore, the refractive index of the medium is 2 .

Answer 2

Answer:

Given :-

• Velocity of light in air (c) = 3 × 10⁸ m/s
• Velocity of light in medium (v) = 1.5 × 10⁸ m/s

To Find :-

Refractive index

Solution :-

Here, for finding refractive index we will use snell's law

$\huge \tt \mapsto \: nm = \frac{c}{v}$

Here,

nm = refractive index

c = Light in air

v = Light in medium

$\huge \tt \mapsto \: nm \: = \frac{ {3 \times 10}^{8} }{ {1.5 \times 10}^{8} }$

$\huge \tt \mapsto \: nm \: = \frac{3}{1.5}$

$\huge \tt \mapsto \: nm \: = 2$

$\huge \bf \: Refractive \small \: index \huge \: = 2$