Question

Velocity of light in air is 3×10^8m/s, while its velocity in a medium is 1.5×10^8m/s.Then,find the refractive index of this medium ?​

Answer 1

(u1/u2)=(v2/v1)

u/1=(3*10^8)/(1.5*10^8)

u=2

Answer 2

Given:-

• Speed of light in air , c = 3 × 10⁸ m/s

• Speed of light in medium ,v = 1.5 × 10⁸ m/s

To Find:-

• Refractive index of medium ,nm

Solution:-

Using Snell's Law

• nm = c/v

where,

ng is the refractive index

c is the speed of light in air

v is the speed of light in medium

Substitute the value we get

→ nm = 3×10⁸/1.5×10⁸

→ nm = 3/1.5

→ nm = 2

Therefore, the refractive index of the medium is 2 .