Question

Velocity of light in air is 3*108m/s refractive index of water is 1.33. Time taken by light to travel a distance of 500m in water is

Answer 1

Answer:

Refractive index = Speed of light in vaccum / Speed of light in water. It is denotes as n = c / v, v = c / n= 3 × 10^8 m/s / (1.33) = 2.25 × 10^8 m/s.

Therefore, refractive index of the water can be measure by the Speed of light in water is 2.25 × 10^8 m/s.

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Explanation:

Answer 2

The time taken by light to travel a distance of 500 m in water is $2.23\times 10^{-6}\ s$.

Explanation:

It is given that,

The speed of light in air, $c=3\times 10^8\ m/s$

The refractive index of water, n = 1.33

Let v is the speed of light in water. The refractive index in terms of speed of light is given by :

$n=\dfrac{c}{v}$

$v=\dfrac{c}{n}$

$v=\dfrac{3\times 10^8}{1.33}$

$v=2.25\times 10^8\ m/s$

Distance covered by the light, d = 500 m

Let t is the time taken by light to travel a distance of 500 m in water. It can be given by :

$v=\dfrac{d}{t}$

$t=\dfrac{d}{v}$

$t=\dfrac{500\ m}{2.25\times 10^8\ m/s}$

$t=2.23\times 10^{-6}\ s$

So, the time taken by light to travel a distance of 500 m in water is $2.23\times 10^{-6}\ s$. hence, this is the required solution.

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Refractive index

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