Velocity of light in air is 3x10'8.refractive index of water is 1.33.the time taken by light to travel a distance of 500m in water is
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Answer:
Refractive index = Speed of light in vaccum / Speed of light in water. It is denotes as n = c / v, v = c / n= 3 × 10^8 m/s / (1.33) = 2.25 × 10^8 m/s. Therefore, refractive index of the water can be measure by the Speed of light in water is 2.25 × 10^8 m/s.
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Explanation:
refractive index of water = speed of light in air / speed of light in medium
4/3 = 3 x 10⁸ / v
v = 9 x 10⁸ /4 m/s
v = distance / time
time = distance / velocity
=( 500 x 4 ) / 9 x 10⁸
= 2000 / 9 x10⁸
= 2/9 x 10^-5 s
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