Question

Velocity of particle depends on its position as v = (x2 + 1) m/s. Find acceleration at x = 1 m.​

Answer 1

Answer:

$a = \frac{dv}{dt} \\ = \frac{d}{t} (x^{2} + 1) \\ = 2x + 0 \\ = 2(1) \\ = 2 \\ so. \: x \: = 2$

m/s²