Velocity of rain is 2 m/s vertically downwards and a man is moving forward with velocity of
1 m/s find angle made umbrella with vertical without dretching himself?
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dθdt=11+t2.
Velocity of rain with respect to boy
v→rain,boy=v→rain−v→boy=v→rain+(−v→boy)
At any time t, rain will appear to the boy as shown in (Fig. 5.111).
tanθ=atv
Boy should hold his umbrella at an angle θ from the vertical
∴tanθ=atv
To find the rate at which the angle of the axis of umbrella with vertical, we need to find dθ/dt.
dtanθdt=d(atv)dt⇒sec2θdθdt=av
⇒dθdt=avsec2θ=av[1+tan2θ]
=av[1+a2t2v2]=avv2+a2t2
=2×24+4t2=11+t2
⇒dθdt=11+t2.
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