Question

velocity of sound in air is 330m/s. What will be the velocity when the temperature is doubled and pressure is halved

Answer 1

Speed of sound is = $\sqrt{\frac{\gamma RT}{M}} = \sqrt{\frac{\gamma P}{\rho}}$

We shall use the first one, since in the second, two quantities - P and $\rho$ are changing.

So, on doubling the temperature, the velocity shall become √2 times of the original = (1.414...) * 330 m/s = 466.62... m/s.

Answer 2

heyu mate here is your answer

330√2m/s


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