velocity of sound in air is 332ms find the frequency of an fundamental note of an open organ pipe which is 50cm long
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for open organ
F = v /( 2 L )
here v = 332 m/s
L = .5m
Thus F = 332 Hz
F = v /( 2 L )
here v = 332 m/s
L = .5m
Thus F = 332 Hz
MahadevanKM:
correct
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