Question

Velocity of star is 10^6 m/sec and frequency of emitted light is

Answer 1

Explanation:

Electromagnetic radiation comprises varying electric and magnetic fields that can be thought of either as waves or as light particles - photons. Low frequency = large wavelength = low energy. High frequency = small wavelength = high energy. (2) The speed of light is 3.00 x 108 m/sec = 3 x 105 km/sec.

Answer 2

The Doppler effect the shift is $20\ \AA$.

Explanation:

Given that,

Velocity of star $= 10^{6}\ m/s$

Suppose, if the frequency of emitted light is $f=5.0\times10^{14}\ Hz$ then determine the Doppler effect the shift in wavelength

We need to calculate the wavelength

Using formula of frequency

$f=\dfrac{c}{\lambda}$

$\lambda=\dfrac{c}{f}$

Put the value into the formula

$\lambda=\dfrac{3\times10^{8}}{5.0\times10^{14}}$

$\lambda=6000\times10^{-10}\ m$

We need to calculate the Doppler's shift

Using formula of Doppler effect

$\Delta\lambda=\dfrac{v\lambda}{c}$

Put the value into the formula

$\Delta\lambda=\dfrac{10^{6}\times6000\times10^{-10}}{3\times10^{8}}$

$\Delta\lambda=2\times10^{-9}\ m$

$\Delta\lambda=20\ \AA$

Hence, The Doppler effect the shift is $20\ \AA$.

Learn more :

Topic : Doppler effect

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