Question

Velocity of the body moving with initial velocity
of 1om/s at constant acceleration of a 2m/s mis for 5secs
is.​

Answer 1

Explanation:

Given,

u=10m/s

a=−2m/s

2

n=5

The distance covered by the particle in n

th

second is

S

n

=u+

2

a

(2n−1)

S

5

=10−

2

2

(2×5−1)

S

5

=10−9=1m