Velocity of the body which was intially at rest is 10 m/s after 4 sec if tje mass of the body is 1 kg find the force applied ?
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: 4000 J How To: 1. Constant Acceleration: a = F / m. This is Newton's second law formula solved for acceleration. ... Final velocity: Vf = Vi + a•t (40 m/s) 3. ... A body of 5 kg mass, initially at rest, is subjected to a force of 20 N.
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2.5 N
Explanation:
Acceleration of body
a = (v - u)/t
= (10 m/s - 0 m/s)/(4 s)
= 2.5 m/s²
Force = ma
= 1 kg × 2.5 m/s²
= 2.5 N
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