Velocity of two particles A and B departed by distance 20m apart is as shown in figure then what will be the Anguilla velocity of B wrt A
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Concept:
- Relative velocity
- Angular velocity
- Application of vectors
Given:
- The distance between particles A and B = 20m
- Speed of particle A v1 = 50 m/s
- Speed of particle B v2 = 100√3 m/s
Find:
- Angular velocity of particle B with respect to particle A
Solution:
Downward vertical velocity of A = 50 sin 30 = 25 m/s
Horizontal velocity of A towards left = 50 cos 30 = 43.3 m/s
Upward vertical velocity of B = 100√3 sin 60 = 150 m/s
Horizontal velocity of B towards left = 100√3 sin 30 = 50√3
Relative velocity towards the left = 50√3 - 43.3 = 43.3 m/s
Relative velocity vertically = 150-(-25) = 175 m/s
Consider only vertical relative velocity as it is perpendicular to the distance
Relative angular velocity = v/r = 175/20 = 8.75
The angular velocity of B with respect to A is 8.75
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