velocity of water in a horizontal pipe is 4.9m/s.find the velocity head of water
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Answered by
7
velocity head = 1/2 ρ v²
= 1/2 * 1000 kg/m³ * 4.9² m²/s²
= 12, 005 N/m² or J/m³ or Pa
= 1/2 * 1000 kg/m³ * 4.9² m²/s²
= 12, 005 N/m² or J/m³ or Pa
kvnmurty:
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Answered by
2
Answer:
1.225m
Explanation:
velocity head = v²/2g = 4.9²/2×9.8=1.225m
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