Question

velocity time equation of a partical moving in a straight line is v=(10+2t+3t²) what will be acceleration time graph​

Answer 1

$\boxed{\huge\mathfrak{\red{ given :: }}}$

$\tt v = 3t^2+2t+20$

$\boxed{\huge\mathfrak{\red{ to find :: }}}$

acceleration

solution:

$\rm we\:have\:to\:differentiate \:the$

$\rm following\:equation$

$\tt \dfrac{dv}{dt} = a$

$\tt \dfrac{d(3t^2+2t+10t^0)}{dt} = a$

$\tt (3)(2)t^1 + (2)(1)t^0 + (10)(0) = a$

$\boxed{\tt 6t + 2 + 0 = a }$

so the acceleration time graph is given by:

6t+2