Question

Velocity-time-graph corresponding to displacement-time graph
shown in adjoining figure is:
​

Answer 1

Answer:

Here is the velocity time graph

$\setlength{\unitlength}{1 cm}\begin{picture}(16,8)\thicklines\put(0.9,9){\tt Y}\put(8.9,0.9){\tt X}\put(0.7,0.5){\sf 0}\put(1,1){\circle*{0.1}}\put(1,1){\vector(1,0){7.8}}\put(1,1){\vector(0,1){7.8}}\put(8,0.9){\line(0,1){0.2}}\put(2,0.9){\line(0,1){0.2}}\put(3,0.9){\line(0,1){0.2}}\put(4,0.9){\line(0,1){0.2}}\put(5,0.9){\line(0,1){0.2}}\put(6,0.9){\line(0,1){0.2}}\put(7,0.9){\line(0,1){0.2}}\put(0.9,8){\line(1,0){0.2}}\put(0.9,2){\line(1,0){0.2}}\put(0.9,3){\line(1,0){0.2}}\put(0.9,4){\line(1,0){0.2}}\put(0.9,5){\line(1,0){0.2}}\put(0.9,6){\line(1,0){0.2}}\put(0.9,7){\line(1,0){0.2}}\qbezier(1.09,1)(2,2)(7.8,8)\put(1.9,0.5){\sf3}\put(2.9,0.5){\sf6}\put(3.9,0.5){\sf9}\put(4.8,0.5){\sf12}\put(5.7,0.5){\sf15}\put(6.7,0.5){\sf18}\put(7.8,0.5){\sf20}\put(0.6,1.9){\sf4}\put(0.6,2.9){\sf6}\put(0.6,3.9){\sf8}\put(0.5,4.9){\sf10}\put(0.5,5.9){\sf12}\put(0.5,6.9){\sf14}\put(0.5,7.9){\sf16}\put(3,0.1){\vector(1,0){3.5}}\put(4.3,-0.3){\sf Time(s)}\put(0.1,2){\vector(0,1){3.5}}\put(-0.19,4.6){\sf D}\put(-0.17,4.3){\sf i}\put(-0.17,4){\sf s}\put(-0.17,3.7){\sf t}\put(-0.17,3.4){\sf a}\put(-0.17,3.1){\sf n}\put(-0.17,2.8){\sf c}\put(-0.17,2.5){\sf e}\end{picture}$