Question

) Velocity-time graph for the ball’s motion is shown in figure below. i) At which point is the ball 1 stationary? ii) What is the ball’s acceleration at point A
1

Answer 1

Answer:

Explanation:

Taking downward as positive y direction.

Equation of motion for upward motion,

mg−kv=ma, where kv is the air drag.

Downward motion,

mg+kv=−m  

∂t

∂v

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Solving the equation gives us an exponential function i.e a function which is not linear

Hence fourth graph is most appropriate.

Answer 2

Answer:

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