Question

Velocity-time graph for vehicles A and B are shown in figure. Which vehicle has accelerated motion and which vehicle has retarded (i.e. negative Accelerated) motion?​

Answer 1

can you please give figure of it

Answer 2

Given:

A velocity-time graph has been provided for two vehicles A and B.

To find:

Which graph shows accelerated motion and which one shows retarded motion?

Solution:

• $Acc. = \dfrac{dv}{dt}=slope \:of\:v-t \:graph$

• The above equation shows that the slope of a velocity time graph gives us acceleration.

• So, any velocity-time graph with positive slope will give acceleration and those with positive slope will give retardation.

• $\tan(\theta)$ represents the slope , where $\theta$ is the angle between curve and time axis.

• So, when $\theta$ is acute, the value of $\tan(\theta)$ is positive and vice versa.

For Vehicle A:

$\therefore \: acc. = \dfrac{dv}{dt} = \tan( \theta) > 0$

Since slope is positive, hence the car is accelerating.

For Vehicle B:

$\therefore \: acc. = \dfrac{dv}{dt} = \tan( \theta) < 0$

Since slope is positive, hence the car is retarding.

Hope It Helps.