Physics, asked by sparshpapa999, 7 months ago

Velocity-time graph is given below to show the motion of a truck of

mass 1000 kg. Answer the following questions based on your interpretation:

i) For which time interval there is no force acting on the truck?

ii) Calculate the retarding force acting on the truck.


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Answered by Poorva90
0

Answer:

Given,

u = 0, a = 3 ms-2, t= 10s

We know, v = u + at

v = 0 + 10 x 3 = 30 m/s

( i ) At t = 12 s,

The horizontal component (VX) of velocity does not change, i.e., VX = 30 m/s . (Since there is no air resistance)

Now, according to the first equation of motion:

VY = u + aYδt (Where VY is the vertical component of velocity)

Where, δt = 12 – 10 = 2 s and aY = g = 10 m/s2

VY = 0 + 10 × 2 = 20 m/s

Therefore the resultant velocity (v) of the phone can be represented as :

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