Question

velocity-time graph of a block of mass 100 g sliding on a horizontal concrete force of 5 N is shown below. The magnitude of frictional force acting on the block due to the floor is

Answer 1

Hola Here_________

Here is Your Answer..!!!
___________________
⭐Actually welcome to the concept of the KINEMATICS OF A BODY

⭐FRICTION

Answer 2

Here is your solution

Given :-

U = 60m/s
V= 80m/s
Time = 8 sec- 6 sec = 2 sec

acceleration =v-u/t
a=>80-60/2=
a=>10m/s

mass 100 gm = 0.1kg

Force = mass ×acceleration
f=>0.1×10= 1N

constant force 5 newton( Given )

Net force = constant force - frictional force
N.f= 5 - frictional force
1 -5 = - frictional force
frictional force = 4 newton

Hope it helps you