Question

velocity time graph of a block of mass 4kg sliding on a horizontal compact follow under the action of a constant force of 5 newton is so below the magnitude of frictional force acting on the block to the floor is

Answer 1

acceleration is equal to rate of change in velocity wrt time

from the graph acceleration is 10 m/s2

and from newton second law, acceleration is (total external force)/(mass)

in detail see the pic