Question

velocity time graph of a body is given as follows
a. state the kind of motion represented by oa and ab
b. what is the velocity of the body after 10 seconds and after 40 seconds
c. calculate the retardation of the following
d. calculate the distance covered by the body between 10th and 30th seconds

Answer 1

Hello!

a.
We know that slope under velocity - time graph gives acceleration.
So,the motion represented by OA is constant acceleration.And from A to B there us no increase in velocity with increase in time.So,AB shows uniform velocity.
b.
The velocity after 10 seconds is 20m/s.
The velocity after 40 seconds is 0m/s.
c.
retardation =v-u/t
=20-0/10
=20/10
=2/1
=-2m/s2.
d.
distance covered =area under velocity- time graph that is area of the rectangle.
=20*20=400m

hope it helps.
#aditya

Answer 2

We know that slope under velocity - time graph gives acceleration.

So,the motion represented by OA is constant acceleration.And from A to B there us no increase in velocity with increase in time.So,AB shows uniform velocity.

b.

The velocity after 10 seconds is 20m/s.

The velocity after 40 seconds is 0m/s.

c.

retardation =v-u/t

=20-0/10

=20/10

=2/1

=-2m/s2.

d.

distance covered =area under velocity- time graph that is area of the rectangle.

=20*20=400m