Physics, asked by BRAINLIESTY, 21 days ago

Velocity time graph of a body is shown in the figure. Find its acceleration in m/s2.
I mislabeled it 2 times.. wrong flair... looking forward for answer

Attachments:

Answers

Answered by rsagnik437
87

Answer :-

Acceleration of the body is 0.0042 m/ .

Explanation :-

From the graph, we have :-

→ Initial velocity of the body (v₁) = 20 m/s

→ Final velocity of the body (v₂) = 80 m/s

→ Time interval (t) = 4 hrs

= 4(3600)

= 14400 s

________________________________

Now, we know that :-

Acceleration = Change in Velocity/Time

⇒ a = ∆v/t

⇒ a = (v₂ - v₁)/t

⇒ a = (80 - 20)/14400

⇒ a = 60/14400

⇒ a = 6/1440

a = 0.0042 m/s²

Some Extra Information :-

The 3 equations of motion, for a body moving with uniform acceleration are :-

• v = u + at

• s = ut + ½at²

• v² - u² = 2as


Anonymous: Good !
rsagnik437: Thank you so much :D
mddilshad11ab: Perfect explaination ✔️
rsagnik437: Thank you so much ! :)
Answered by Anonymous
79

Answer:

Given :-

  • Initial velocity (u) = 20 m/s
  • Final velocity (v) = 80 m/s
  • Time (t) = 4 hrs

To Find :-

  • What is the acceleration in m/s².

Formula Used :-

\clubsuit Constant Acceleration Formula :

\longmapsto \sf\boxed{\bold{\pink{a =\: \dfrac{(v - u)}{t}}}}\\

where,

  • a = Acceleration
  • v = Final Velocity
  • u = Initial Velocity
  • t = Time

Solution :-

First, we have to convert the time into seconds :

\implies \sf Time =\: 4\: hrs

\implies \sf Time =\: 4 \times 3600\: seconds\: \bigg\lgroup \bold{\purple{1\: hours =\: 3600\: seconds}}\bigg \rgroup\\

\implies \sf\bold{\red{Time =\: 14400\: seconds}}

Given :

  • Final velocity = 80 m/s
  • Initial velocity = 20 m/s
  • Time = 14400 seconds

According to the question by using the formula we get,

\dashrightarrow \sf a =\: \dfrac{(80 - 20)}{14400}

\dashrightarrow \sf a =\: \dfrac{6\cancel{0}}{1440\cancel{0}}

\dashrightarrow \sf a =\: \dfrac{\cancel{6}}{\cancel{1440}}

\dashrightarrow \sf a =\: \dfrac{\cancel{3}}{\cancel{720}}

\dashrightarrow \sf\bold{\red{a =\: 0.0042\: m/s^2}}

\therefore The acceleration is 0.0042 m/.

Similar questions