Velocity-time graph of a particle moving in a straight line is shown in figure. Mass of the particle is 2 kg. Power delivered by all the forces acting on the particle at 1=5 sec is v (m/s) 5 t = 10 t (sec) 5 Zero
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Answer:
Correct option is B)
Acceleration of the particle = a =
Δt
Δv
=
2
−20
=−10m/s
2
Distance travelled by particle before coming to rest=Area of the triangle=
2
1
×2×20m=20m
Thus the work done by forces=Fs=mas
=2×−10×20J=−400J
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