Velocity-time graph of a particle of mass 2 kg moving in a straight line is as shown in figure Work
done by all the forces on the particle is :
4 V (mis)
20
1 s)
2
(A)
400 J
(B)
-400 J
(C)
-200 J
(D
200 J
Answers
Answered by
1
Answer:
T
2
P
1
V
1
=
T
2
P
2
V
2
P
1
=1atm
V
1
=350cm
3
T
1
=273k
P
2
=0.5atm
T
2
=550k
V
2
=?
V
2
=
T
1
P
2
P
1
V
1
T
2
V
2
=1 × 350 ×550 / 273 × 0.5
V
2
= 1409 cm
3
Therefore B is the correct option.
Answered by
0
Acceleration of the particle = a =
Δt
Δv
=
2
−20
=−10m/s
2
Distance travelled by particle before coming to rest=Area of the triangle=
2
1
×2×20m=20m
Thus the work done by forces=Fs=mas
=2×−10×20J=−400J
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