velocity time graph of a particles moving in a straight line is shown on the figure. find the distance traval between the interval t=0 to t=10.
Answers
Answered by
1
Answer: I think the answer is 5.
Explanation: I hope this answer was helpful my friend.
Answered by
0
Explanation:
Displacement= Area under velocity-time graph
Hence, s
OA
=
2
1
×2×10=10m
s
AB
=2×10=20m
or s
OAB
=10+20=30m
s
BC
=
2
1
×2(10+20)=30m
or s
OABC
=30+30=60m
and s
OABCD
=60+20=80m
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