velocity v=
then work done during motion from x=4m to x=9m is ? (if mass is 1 kg)
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Answer:
hii I think that it helps you
Explanation:
W=KE
f
−KE
i
W=KE
f
−
2
1
mv
2
F−dx=KE
f
−
2
1
×10×10
2
−0.1xdx=KE
f
−500
0.1∫
20
30
xdx=KE
f
−500
0.1[
2
x
2
]
20
30
=KE
f
−500
=
2
0.1
[(30)
2
−(20)
2
]=KE
f
−500
−25=KE
f
−500
KE
f
=475J
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