Question

Velocity versus time graph of a ball of mass 50g rolling on a concrete floor is
shown in figure. Calculate the acceleration and frictional force of the floor on the
ball.

Answer 1

AnSwer :

Note :- Figure is shown in the attachment.

Solution,

From the above graph,

• u = 80 m/s
• v = 0
• t = 8 s

◑ v = u + at

→ 0 = 80 + a × 8

→ a = -80/8

→ -10 m/s²

◑ m = 50 g

→ 50/1000 kg

→ 1/20 kg

$\sf{\therefore}$ F = ma

→ 1/20 × (-10)

→ - 0.5 N

◑ Negative sign is showing the frictional force of the floor on the ball.

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Answer 2

Answer:

Answer is a= -10m/s'²

Explanation:

a=v-u/t

0-80/8-0

=-10m/s'2

force = ma

m=50/1000

F = ma

F = 50/1000 × 10

F = 0.5 N