Question

Vent Hoff fector for 0.01 M aqueous solution of ethanoic acid is 1.04 what is the ph of solution ?​

Answer 1

Answer

3.4

when when ethanoic acid ionised it gives

Ch3Coo^-1 + H3O^+

if a is degree of ionization and C is initial concentration of acid then at equilibrium concentration of hydronium ion is given as.

[H3O^+] = Ca

Given

I = 1.04

so

a = (I - 1)/(m - 1)

a = (1.04 - 1)/(2 - 1)

a = 0.04

hydronium ion= 0.01 *0.04 = 4*10^-4 molL^-1

Ph =

$- log( {h3o}^{ + } ) = 4 - log(4) = 3.397 = 3.4$