Question

Vent Hoff fector for 0.1 M aqueous solution of ethanoic acid is 1.04 what is the ph of solution ?​

Answer 1

when when ethanoic acid ionised it gives

Ch3Coo^-1 + H3O^+

if a is degree of ionization and C is initial concentration of acid then at equilibrium concentration of hydronium ion is given as.

[H3O^+] = Ca

Given

I = 1.04

so

a = (I - 1)/(m - 1)

a = (1.04 - 1)/(2 - 1)

a = 0.04

hydronium ion= 0.1 *0.04 = 4*10^-3 molL^-1

ph = - log[hydronium ion]

Ph = 3 - log4 = 2.4