verify 1/2 , 1, -2 are zeros of 2x cube + x square -5x + 2 and check relationship between zeroes and coefficients
Answers
EXPLANATION.
1/2,1,-2 are the zeroes of the quadratic equation,
Equation ⇒ 2x³ + x² - 5x + 2.
Let α = 1/2 and β = 1 and γ = -2.
Sum of zeroes of the cubic equation.
⇒ α + β + γ = -b/a.
⇒ 1/2 + 1 + (-2).
⇒ 1/2 + 1 - 2.
⇒ 1 + 2 - 4/2.
⇒ 3 - 4/2.
⇒ -1/2 = -b/a.
Products of zeroes of the cubic equation,
αβγ = -d/a.
⇒ (1/2)(1)(-2).
⇒ -1. = -d/a
Products of zeroes of cubic equation, two at a time.
αβ + βγ + γα = c/a.
⇒ (1/2)(1) + (1)(-2) + (-2)(1/2).
⇒ 1/2 - 2 - 1.
⇒ 1 - 4 - 2/2.
⇒ -5/2 = c/a.
Again, As we know that,
Put x = 1/2 in equation, we get.
⇒ p(1/2) = 2x(1/2)³ + (1/2)² - 5(1/2) + 2.
⇒ p(1/2) = 1/4 + 1/4 - 5/2 + 2.
⇒ p(1/2) = 1 + 1 - 10 + 8/4.
⇒ p(1/2) = 10 - 10/4.
⇒ p(1/2) =0.
Put x= 1 in equation, we get.
⇒ p(1) = 2(1)³ + (1)² - 5(1) + 2.
⇒ p(1) = 2 + 1 - 5 + 2.
⇒ p(1) = 5 - 5.
⇒ p(1) = 0.
Put x = -2 in equation, we get.
⇒ p(-2) = 2(-2)³ + (-2)² - 5(-2) + 2.
⇒ p(-2) = -16 + 4 + 10 + 2.
⇒ p(-2) = 16 - 16.
⇒ p(-2) = 0.
HENCE VERIFIED.
Step by step explanation:-
Given :-
Cubic equation :- 2x³+x²-5x+2
To find :-
Relationship between zeroes and coefficients
To verify :-
½ , 1 , -2 are zeroes of cubic equation
Solution :-
First we will verify zeroes of cubic equation
2x³ + x² -5x +2 =0
Put x = 1/2
2 × (1/2)³ + (1/2)² -5(1/2) + 2 = 0
2 × 1/8 + 1/4 - 5/2 +2 =0
1/4 + 1/4 -5/2 +2 =0
2/4 -5/2 + 2 =0
1/2 -5/2 + 2 =0
-4/2 + 2 =0
0/2 =0
0 = 0
So, p(1/2) =0
Hence p(1/2) is a factor
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2x³ + x² -5x +2 =0
p(1) =
Put x = 1
2(1)³ +(1)² -5(1) +2 =0
2 + 1 -5 + 2 =0
5 -5 =0
0 =0
Hence p(1) is a factor
_________________________
2x³+x²-5x+2 = 0
p(-2)
Put x = -2
2(-2)³ + (-2)² -5(-2) +2 =0
-16 + 4 + 10 + 2 =0
16 -16 =0
0 = 0
Hence p(-2) is a factor
______________________________
From these we can say that
½ , 1 , -2 are zeroes of cubic equation
______________________________
Relation between zeroes & coefficients in cubic equation
We know Some relations:-
Sum of zeroes = α + ß + γ = -b/a
Sum of product of roots = α ß + ß γ + γα = c/a
Product of roots αßγ =-d/a
Now lets see !!
2x³+x²-5x+2 = 0
a = 2
b = 1
c = -5
d = 2
Sum of zeroes = -b/a = -1/2
Sum of product of roots = c/a = -5/2
product of roots = -d/a = -2/2 = -1
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