Question

Verify 1,2,-3 are zeroes of x³-7x+6 also verify relations between

coefficients and zeroes​

Answer 1

Question p(x) = x³-7x+6

Put in the values of all number

= p(1) = 1³-7(1)+6

= 1-7+6

= 0 Yes 1 is a zero polynomial of p(x)

Now do that with both the numbers

Answer 2

Step-by-step explanation:

for 1

1^3 -7.1 + 6

= 3 -7 + 6

= 3-1

= 2 ( not)

for 2

2^3 - 7.2 +6

= 8 -14+ 6

= 8-8= 0 (yes)

=7 (not)

For -3

(-3) ^3 -7. (-3) +6

= -27 + 21 +6

= -27 +27

= 0 (yes)

Relations :

do yourself