verify -1/√3 and 2/√3 are zeroes of the polynomial 3x²-1
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given
polynomial 3x²-1
p(x)=3x2-1
p(-1/√3)=3(-1/√3)2-1
p(-1/√3)=3(1/3)-1=1-1=0
p(2/√3)=3(2/√3)2-1
p(2/√3)=3(4/3)-1=4-1=3
p(-1/√3) is the zeroes of the polynomial
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