Verify : √(1-cosA)/(1+Cos A) = (Sin A)/(1+Cos A) , for A = 60° .
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cosA=60° then:
1-cosA=1-1/✓2
1+cosA=1+1/✓2
SinA=✓3/2
so the statement becomes ✓(1-1/✓2)(1+1/✓2) = (✓3/2)/(1+1/✓2)
=> 1-1/2
=> 2-1/2
=>1/2
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