verify 11 16 21 26 are in AP if it is an AP.test test whether 226 is a term of AP
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palakhanduja32:
hey mate 220/5is 44 not 110
220/2=110
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a = 11 d= a2-a1
a2-a1=a3-a2
16-11=21-16
5=5
since D ON BOTH SIDES IS EQUAL.
THIS SHOWS THAT THE SERIES IS IN A.P
an= 226
an= a+ (n-1)d= 226
11+(n-1)5=226
11+5n-5=226
6+5n=226
5n= 226-6
5n= 220
n=220/5
n=44
since n=44 is a positive integer.
so 226 is a term of ap.
hope it helps you.
please mark it as brainlist.
a2-a1=a3-a2
16-11=21-16
5=5
since D ON BOTH SIDES IS EQUAL.
THIS SHOWS THAT THE SERIES IS IN A.P
an= 226
an= a+ (n-1)d= 226
11+(n-1)5=226
11+5n-5=226
6+5n=226
5n= 226-6
5n= 220
n=220/5
n=44
since n=44 is a positive integer.
so 226 is a term of ap.
hope it helps you.
please mark it as brainlist.
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