Question

verify 2 and -3 are the zero of the polynomial q(x)= x²+x -6​

Answer 1

Hey mate,.

q(X)= x²+x-6=0

Replace the given values to verify the zeros.

q(2)=2²+2-6=0

=4+2-6=0

=6-6=0

=0=0

It can be the one zero.

And another one,

=3²+3-6=0

=9+3-6=0

=12-6=0

=6

so, it is not a zero.

Hope it will help you

✌️sai

Answer 2

Answer-

We are given withe the zeros 2 & -3 respectivly.

q(x)= x² + x -6

Putting the given values in q(x)

*q(x) = 2

> 2² + 2 -6

> 4 + 2 - 6

> 6 - 6

> 0

*q(x) = -3

> (-3)² +(-3) - 6

> 9 -3 -6

>9 -9

>0

Hence, 2 & -3 are the zeros of the given equation.

Verified.