Question

Verify -3, -4 are zeros of the polynomial p(x) =x²+7x+12​

Answer 1

Step-by-step explanation:

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BY PUTTING x = -3

(-3)^2 + 7(-3) + 12 = 9 - 21 + 12 = 0

BY PUTTING x = -4

(-4)^2 + 7(-4) + 12 = 16 - 28 + 12 = 0

THEREFORE -3 & -4 ARE ROOTS OF THE EQUATION.

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