Math, asked by sunnybunny6777, 3 months ago

Verify:

(a^2 - b^2) (a^2 + b^2) + (b^2 - c^2) (b^2 + c^2) + (c^2 - a^2) (c^2 + a^2) = 0


plz answer fast​

Answers

Answered by deyanik252
1

Answer:

Step-by-step explanation:

Attachments:
Answered by harshinimoond
1

Answer:

Please Mark Me As Brainliest

Step-by-step explanation:

 ({a}^{2}  -  {b}^{2} )( {a}^{2}  +  {b}^{2}  ) + ( {b}^{2} -  {c}^{2}  )( {b}^{2} +  {c}^{2}  ) + ( {c}^{2}  -  {a}^{2} )( {c}^{2} +  {a}^{2}  )  = 0\\  {( {a}^{2}) }^{2}  -  {( {b}^{2}) }^{2}  +  {( {b}^{2}) }^{2}  -  {( {c}^{2}) }^{2}  +  {( {c}^{2}) }^{2}  -  {( {a}^{2}) }^{2}  = 0 \\  {a}^{4}  -  {b}^{4}  +  {b}^{4}  -  {c}^{4}  +  {c}^{4}  -  {a}^{4}  = 0 \\ 0 = 0

Similar questions