Question

Verify a^2b^2c^2=(ab)(bc)(ca) for a=3,b=-1,c=2

Answer 1

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Here is your answer

$a ^{2} + b ^{2} + c ^{2} = (ab) \: (bc) \: (ca)$


Substitute the values a = 3 , b = -1 , c = 2


so, 3^2+(-1)^2+2^2=(3×-1)(-1×2)(2×3)

= 9 + 1 + 4 = (-3)(-2)(6)

= 14= 36

So, LHS is not equal to RHS