Question

verify : a^3+b^3+c^3 - 3abc =1⁄2(a+b+c)[(a-b)^2+(b-c)^2+(c-a)^2]

Answer 1

Look at .a^3+b^3+c^3-3abc=1
Moved these terms to the left = -1
It becomes .
a^3+b^3+c^3-3abc-1=0